3.10.22 \(\int \frac {x^5}{\sqrt {1+x^4}} \, dx\) [922]

Optimal. Leaf size=25 \[ \frac {1}{4} x^2 \sqrt {1+x^4}-\frac {1}{4} \sinh ^{-1}\left (x^2\right ) \]

[Out]

-1/4*arcsinh(x^2)+1/4*x^2*(x^4+1)^(1/2)

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Rubi [A]
time = 0.01, antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {281, 327, 221} \begin {gather*} \frac {1}{4} x^2 \sqrt {x^4+1}-\frac {1}{4} \sinh ^{-1}\left (x^2\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^5/Sqrt[1 + x^4],x]

[Out]

(x^2*Sqrt[1 + x^4])/4 - ArcSinh[x^2]/4

Rule 221

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[Rt[b, 2]*(x/Sqrt[a])]/Rt[b, 2], x] /; FreeQ[{a, b},
 x] && GtQ[a, 0] && PosQ[b]

Rule 281

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
 + 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rule 327

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^n
)^(p + 1)/(b*(m + n*p + 1))), x] - Dist[a*c^n*((m - n + 1)/(b*(m + n*p + 1))), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
 c, n, m, p, x]

Rubi steps

\begin {align*} \int \frac {x^5}{\sqrt {1+x^4}} \, dx &=\frac {1}{2} \text {Subst}\left (\int \frac {x^2}{\sqrt {1+x^2}} \, dx,x,x^2\right )\\ &=\frac {1}{4} x^2 \sqrt {1+x^4}-\frac {1}{4} \text {Subst}\left (\int \frac {1}{\sqrt {1+x^2}} \, dx,x,x^2\right )\\ &=\frac {1}{4} x^2 \sqrt {1+x^4}-\frac {1}{4} \sinh ^{-1}\left (x^2\right )\\ \end {align*}

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Mathematica [A]
time = 0.10, size = 35, normalized size = 1.40 \begin {gather*} \frac {1}{4} x^2 \sqrt {1+x^4}-\frac {1}{4} \tanh ^{-1}\left (\frac {x^2}{\sqrt {1+x^4}}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^5/Sqrt[1 + x^4],x]

[Out]

(x^2*Sqrt[1 + x^4])/4 - ArcTanh[x^2/Sqrt[1 + x^4]]/4

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Maple [A]
time = 0.16, size = 20, normalized size = 0.80

method result size
default \(-\frac {\arcsinh \left (x^{2}\right )}{4}+\frac {x^{2} \sqrt {x^{4}+1}}{4}\) \(20\)
risch \(-\frac {\arcsinh \left (x^{2}\right )}{4}+\frac {x^{2} \sqrt {x^{4}+1}}{4}\) \(20\)
elliptic \(-\frac {\arcsinh \left (x^{2}\right )}{4}+\frac {x^{2} \sqrt {x^{4}+1}}{4}\) \(20\)
trager \(\frac {x^{2} \sqrt {x^{4}+1}}{4}-\frac {\ln \left (x^{2}+\sqrt {x^{4}+1}\right )}{4}\) \(28\)
meijerg \(\frac {\sqrt {\pi }\, x^{2} \sqrt {x^{4}+1}-\sqrt {\pi }\, \arcsinh \left (x^{2}\right )}{4 \sqrt {\pi }}\) \(30\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(x^4+1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

-1/4*arcsinh(x^2)+1/4*x^2*(x^4+1)^(1/2)

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 58 vs. \(2 (19) = 38\).
time = 0.29, size = 58, normalized size = 2.32 \begin {gather*} \frac {\sqrt {x^{4} + 1}}{4 \, x^{2} {\left (\frac {x^{4} + 1}{x^{4}} - 1\right )}} - \frac {1}{8} \, \log \left (\frac {\sqrt {x^{4} + 1}}{x^{2}} + 1\right ) + \frac {1}{8} \, \log \left (\frac {\sqrt {x^{4} + 1}}{x^{2}} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(x^4+1)^(1/2),x, algorithm="maxima")

[Out]

1/4*sqrt(x^4 + 1)/(x^2*((x^4 + 1)/x^4 - 1)) - 1/8*log(sqrt(x^4 + 1)/x^2 + 1) + 1/8*log(sqrt(x^4 + 1)/x^2 - 1)

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Fricas [A]
time = 0.36, size = 29, normalized size = 1.16 \begin {gather*} \frac {1}{4} \, \sqrt {x^{4} + 1} x^{2} + \frac {1}{4} \, \log \left (-x^{2} + \sqrt {x^{4} + 1}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(x^4+1)^(1/2),x, algorithm="fricas")

[Out]

1/4*sqrt(x^4 + 1)*x^2 + 1/4*log(-x^2 + sqrt(x^4 + 1))

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Sympy [A]
time = 0.88, size = 19, normalized size = 0.76 \begin {gather*} \frac {x^{2} \sqrt {x^{4} + 1}}{4} - \frac {\operatorname {asinh}{\left (x^{2} \right )}}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(x**4+1)**(1/2),x)

[Out]

x**2*sqrt(x**4 + 1)/4 - asinh(x**2)/4

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Giac [A]
time = 2.15, size = 29, normalized size = 1.16 \begin {gather*} \frac {1}{4} \, \sqrt {x^{4} + 1} x^{2} + \frac {1}{4} \, \log \left (-x^{2} + \sqrt {x^{4} + 1}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(x^4+1)^(1/2),x, algorithm="giac")

[Out]

1/4*sqrt(x^4 + 1)*x^2 + 1/4*log(-x^2 + sqrt(x^4 + 1))

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {x^5}{\sqrt {x^4+1}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(x^4 + 1)^(1/2),x)

[Out]

int(x^5/(x^4 + 1)^(1/2), x)

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